101403413 has 2 divisors, whose sum is σ = 101403414. Its totient is φ = 101403412.

The previous prime is 101403403. The next prime is 101403439. The reversal of 101403413 is 314304101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 62378404 + 39025009 = 7898^2 + 6247^2 .

It is an emirp because it is prime and its reverse (314304101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101403413 - 2⁸ = 101403157 is a prime.

It is a super-3 number, since 3×101403413³ (a number of 25 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 101403391 and 101403400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101403403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50701706 + 50701707.

It is an arithmetic number, because the mean of its divisors is an integer number (50701707).

Almost surely, 2^101403413 is an apocalyptic number.

It is an amenable number.

101403413 is a deficient number, since it is larger than the sum of its proper divisors (1).

101403413 is an equidigital number, since it uses as much as digits as its factorization.

101403413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 101403413 is about 10069.9261665615. The cubic root of 101403413 is about 466.3201595001.

Adding to 101403413 its reverse (314304101), we get a palindrome (415707514).

The spelling of 101403413 in words is "one hundred one million, four hundred three thousand, four hundred thirteen".