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101412423391 is a prime number
BaseRepresentation
bin101111001110010100…
…1101100011011011111
3100200202121100212220011
41132130221230123133
53130143040022031
6114331020104051
710220044242646
oct1363451543337
9320677325804
10101412423391
113a01073a764
12177a2995027
13974231ab26
144ca088835d
1529882356b1
hex179ca6c6df

101412423391 has 2 divisors, whose sum is σ = 101412423392. Its totient is φ = 101412423390.

The previous prime is 101412423311. The next prime is 101412423401. The reversal of 101412423391 is 193324214101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101412423391 - 213 = 101412415199 is a prime.

It is a super-3 number, since 3×1014124233913 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101412423311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50706211695 + 50706211696.

It is an arithmetic number, because the mean of its divisors is an integer number (50706211696).

Almost surely, 2101412423391 is an apocalyptic number.

101412423391 is a deficient number, since it is larger than the sum of its proper divisors (1).

101412423391 is an equidigital number, since it uses as much as digits as its factorization.

101412423391 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 31.

Adding to 101412423391 its reverse (193324214101), we get a palindrome (294736637492).

The spelling of 101412423391 in words is "one hundred one billion, four hundred twelve million, four hundred twenty-three thousand, three hundred ninety-one".