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1014133433 is a prime number
BaseRepresentation
bin111100011100100…
…111001010111001
32121200021022112112
4330130213022321
54034104232213
6244344222105
734062664145
oct7434471271
92550238475
101014133433
114804a7505
1224376a935
13132148271
149898a225
155e073ea8
hex3c7272b9

1014133433 has 2 divisors, whose sum is σ = 1014133434. Its totient is φ = 1014133432.

The previous prime is 1014133397. The next prime is 1014133489. The reversal of 1014133433 is 3343314101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1008507049 + 5626384 = 31757^2 + 2372^2 .

It is a cyclic number.

It is not a de Polignac number, because 1014133433 - 28 = 1014133177 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1014133399 and 1014133408.

It is not a weakly prime, because it can be changed into another prime (1014136433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507066716 + 507066717.

It is an arithmetic number, because the mean of its divisors is an integer number (507066717).

Almost surely, 21014133433 is an apocalyptic number.

It is an amenable number.

1014133433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014133433 is an equidigital number, since it uses as much as digits as its factorization.

1014133433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

The square root of 1014133433 is about 31845.4617331889. The cubic root of 1014133433 is about 1004.6891220993.

Adding to 1014133433 its reverse (3343314101), we get a palindrome (4357447534).

The spelling of 1014133433 in words is "one billion, fourteen million, one hundred thirty-three thousand, four hundred thirty-three".