1014133433141 has 2 divisors, whose sum is σ = 1014133433142. Its totient is φ = 1014133433140.

The previous prime is 1014133433119. The next prime is 1014133433143. The reversal of 1014133433141 is 1413343314101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 761203900900 + 252929532241 = 872470^2 + 502921^2 .

It is an emirp because it is prime and its reverse (1413343314101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1014133433141 - 2²⁶ = 1014066324277 is a prime.

It is a super-2 number, since 2×1014133433141² (a number of 25 digits) contains 22 as substring.

Together with 1014133433143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1014133433143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507066716570 + 507066716571.

It is an arithmetic number, because the mean of its divisors is an integer number (507066716571).

Almost surely, 2^{1014133433141} is an apocalyptic number.

It is an amenable number.

1014133433141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1014133433141 is an equidigital number, since it uses as much as digits as its factorization.

1014133433141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1014133433141 its reverse (1413343314101), we get a palindrome (2427476747242).

The spelling of 1014133433141 in words is "one trillion, fourteen billion, one hundred thirty-three million, four hundred thirty-three thousand, one hundred forty-one".