Base | Representation |
---|---|
bin | 10010111001000100… |
… | …01111001001011011 |
3 | 222011211201222120212 |
4 | 21130202033021123 |
5 | 131232424212103 |
6 | 4354231041335 |
7 | 506224043243 |
oct | 113442171133 |
9 | 28154658525 |
10 | 10142413403 |
11 | 4335145341 |
12 | 1b7081024b |
13 | c58361165 |
14 | 6c3034b23 |
15 | 3e563e7d8 |
hex | 25c88f25b |
10142413403 has 4 divisors (see below), whose sum is σ = 10285264368. Its totient is φ = 9999562440.
The previous prime is 10142413387. The next prime is 10142413409. The reversal of 10142413403 is 30431424101.
10142413403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 10142413403 - 24 = 10142413387 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10142413409) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71425376 + ... + 71425517.
It is an arithmetic number, because the mean of its divisors is an integer number (2571316092).
Almost surely, 210142413403 is an apocalyptic number.
10142413403 is a deficient number, since it is larger than the sum of its proper divisors (142850965).
10142413403 is an equidigital number, since it uses as much as digits as its factorization.
10142413403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 142850964.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 10142413403 its reverse (30431424101), we get a palindrome (40573837504).
The spelling of 10142413403 in words is "ten billion, one hundred forty-two million, four hundred thirteen thousand, four hundred three".
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