Base | Representation |
---|---|
bin | 10010111001001011… |
… | …01010100111001100 |
3 | 222011220102122200112 |
4 | 21130211222213030 |
5 | 131233141443312 |
6 | 4354302215152 |
7 | 506234506106 |
oct | 113445524714 |
9 | 28156378615 |
10 | 10143312332 |
11 | 43356a975a |
12 | 1b70b844b8 |
13 | c585b737a |
14 | 6c31ca576 |
15 | 3e576ad22 |
hex | 25c96a9cc |
10143312332 has 48 divisors (see below), whose sum is σ = 18689771520. Its totient is φ = 4812388992.
The previous prime is 10143312329. The next prime is 10143312337. The reversal of 10143312332 is 23321334101.
10143312332 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 10143312298 and 10143312307.
It is not an unprimeable number, because it can be changed into a prime (10143312337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 803453 + ... + 815979.
It is an arithmetic number, because the mean of its divisors is an integer number (389370240).
Almost surely, 210143312332 is an apocalyptic number.
It is an amenable number.
10143312332 is a deficient number, since it is larger than the sum of its proper divisors (8546459188).
10143312332 is a wasteful number, since it uses less digits than its factorization.
10143312332 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12710 (or 12708 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 10143312332 its reverse (23321334101), we get a palindrome (33464646433).
The spelling of 10143312332 in words is "ten billion, one hundred forty-three million, three hundred twelve thousand, three hundred thirty-two".
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