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101433230831 is a prime number
BaseRepresentation
bin101111001110111100…
…1000100010111101111
3100200211001112000100002
41132131321010113233
53130213401341311
6114333042054515
710220416144022
oct1363571042757
9320731460302
10101433230831
113a021461699
12177a994a43b
13974672491a
144ca35431b9
152989e9593b
hex179de445ef

101433230831 has 2 divisors, whose sum is σ = 101433230832. Its totient is φ = 101433230830.

The previous prime is 101433230819. The next prime is 101433230837. The reversal of 101433230831 is 138032334101.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 101433230831 - 214 = 101433214447 is a prime.

It is a super-2 number, since 2×1014332308312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101433230794 and 101433230803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101433230837) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50716615415 + 50716615416.

It is an arithmetic number, because the mean of its divisors is an integer number (50716615416).

Almost surely, 2101433230831 is an apocalyptic number.

101433230831 is a deficient number, since it is larger than the sum of its proper divisors (1).

101433230831 is an equidigital number, since it uses as much as digits as its factorization.

101433230831 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 101433230831 its reverse (138032334101), we get a palindrome (239465564932).

The spelling of 101433230831 in words is "one hundred one billion, four hundred thirty-three million, two hundred thirty thousand, eight hundred thirty-one".