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101434121431 is a prime number
BaseRepresentation
bin101111001110111110…
…0011101110011010111
3100200211010012021000021
41132131330131303113
53130214113341211
6114333113130011
710220426543356
oct1363574356327
9320733167007
10101434121431
113a021a0a825
12177aa0b9907
1397469770c6
144ca36d599d
15298a0be771
hex179df1dcd7

101434121431 has 2 divisors, whose sum is σ = 101434121432. Its totient is φ = 101434121430.

The previous prime is 101434121419. The next prime is 101434121471. The reversal of 101434121431 is 134121434101.

It is a weak prime.

It is an emirp because it is prime and its reverse (134121434101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 101434121431 - 231 = 99286637783 is a prime.

It is a super-2 number, since 2×1014341214312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101434121396 and 101434121405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (101434121471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50717060715 + 50717060716.

It is an arithmetic number, because the mean of its divisors is an integer number (50717060716).

Almost surely, 2101434121431 is an apocalyptic number.

101434121431 is a deficient number, since it is larger than the sum of its proper divisors (1).

101434121431 is an equidigital number, since it uses as much as digits as its factorization.

101434121431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 101434121431 its reverse (134121434101), we get a palindrome (235555555532).

The spelling of 101434121431 in words is "one hundred one billion, four hundred thirty-four million, one hundred twenty-one thousand, four hundred thirty-one".