Base | Representation |
---|---|
bin | 111110011101001000… |
… | …0101010101111110101 |
3 | 110211012011010210100021 |
4 | 1330322100222233311 |
5 | 4144140041342401 |
6 | 141340423445141 |
7 | 12455440244134 |
oct | 1747220525765 |
9 | 424164123307 |
10 | 134121434101 |
11 | 51976064616 |
12 | 21bb0bb67b1 |
13 | c855a02b35 |
14 | 66c49cd91b |
15 | 374eac42a1 |
hex | 1f3a42abf5 |
134121434101 has 2 divisors, whose sum is σ = 134121434102. Its totient is φ = 134121434100.
The previous prime is 134121434089. The next prime is 134121434137. The reversal of 134121434101 is 101434121431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98721011601 + 35400422500 = 314199^2 + 188150^2 .
It is an emirp because it is prime and its reverse (101434121431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 134121434101 - 231 = 131973950453 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134121434171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67060717050 + 67060717051.
It is an arithmetic number, because the mean of its divisors is an integer number (67060717051).
Almost surely, 2134121434101 is an apocalyptic number.
It is an amenable number.
134121434101 is a deficient number, since it is larger than the sum of its proper divisors (1).
134121434101 is an equidigital number, since it uses as much as digits as its factorization.
134121434101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 134121434101 its reverse (101434121431), we get a palindrome (235555555532).
The spelling of 134121434101 in words is "one hundred thirty-four billion, one hundred twenty-one million, four hundred thirty-four thousand, one hundred one".
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