10144024133 has 4 divisors (see below), whose sum is σ = 10677920160. Its totient is φ = 9610128108.

The previous prime is 10144024103. The next prime is 10144024139. The reversal of 10144024133 is 33142044101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10144024133 - 2²² = 10139829829 is a prime.

It is a super-2 number, since 2×10144024133² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10144024099 and 10144024108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10144024139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 266947985 + ... + 266948022.

It is an arithmetic number, because the mean of its divisors is an integer number (2669480040).

Almost surely, 2^10144024133 is an apocalyptic number.

It is an amenable number.

10144024133 is a deficient number, since it is larger than the sum of its proper divisors (533896027).

10144024133 is an equidigital number, since it uses as much as digits as its factorization.

10144024133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 533896026.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 10144024133 its reverse (33142044101), we get a palindrome (43286068234).

The spelling of 10144024133 in words is "ten billion, one hundred forty-four million, twenty-four thousand, one hundred thirty-three".