Base | Representation |
---|---|
bin | 10010111001010001… |
… | …10101011111010001 |
3 | 222011221222212120121 |
4 | 21130220311133101 |
5 | 131233400041223 |
6 | 4354332110241 |
7 | 506244536563 |
oct | 113450653721 |
9 | 28157885517 |
10 | 10144143313 |
11 | 4336117017 |
12 | 1b71305381 |
13 | c58818685 |
14 | 6c3365333 |
15 | 3e588215d |
hex | 25ca357d1 |
10144143313 has 2 divisors, whose sum is σ = 10144143314. Its totient is φ = 10144143312.
The previous prime is 10144143311. The next prime is 10144143319. The reversal of 10144143313 is 31334144101.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9778836544 + 365306769 = 98888^2 + 19113^2 .
It is a cyclic number.
It is not a de Polignac number, because 10144143313 - 21 = 10144143311 is a prime.
Together with 10144143311, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10144143311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072071656 + 5072071657.
It is an arithmetic number, because the mean of its divisors is an integer number (5072071657).
Almost surely, 210144143313 is an apocalyptic number.
It is an amenable number.
10144143313 is a deficient number, since it is larger than the sum of its proper divisors (1).
10144143313 is an equidigital number, since it uses as much as digits as its factorization.
10144143313 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 10144143313 its reverse (31334144101), we get a palindrome (41478287414).
The spelling of 10144143313 in words is "ten billion, one hundred forty-four million, one hundred forty-three thousand, three hundred thirteen".
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