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1014421300 = 225210144213
BaseRepresentation
bin111100011101101…
…101011100110100
32121200210221102021
4330131231130310
54034142440200
6244354322524
734065303334
oct7435553464
92550727367
101014421300
11480683812
12243889444
131322192b9
1498a230c4
155e0ce41a
hex3c76d734

1014421300 has 18 divisors (see below), whose sum is σ = 2201294438. Its totient is φ = 405768480.

The previous prime is 1014421273. The next prime is 1014421301. The reversal of 1014421300 is 31244101.

It can be written as a sum of positive squares in 3 ways, for example, as 14470416 + 999950884 = 3804^2 + 31622^2 .

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1014421301) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5072007 + ... + 5072206.

Almost surely, 21014421300 is an apocalyptic number.

1014421300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1014421300 is an abundant number, since it is smaller than the sum of its proper divisors (1186873138).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1014421300 is a wasteful number, since it uses less digits than its factorization.

1014421300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10144227 (or 10144220 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 16.

The square root of 1014421300 is about 31849.9811616899. The cubic root of 1014421300 is about 1004.7841751674.

Adding to 1014421300 its reverse (31244101), we get a palindrome (1045665401).

The spelling of 1014421300 in words is "one billion, fourteen million, four hundred twenty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 10144213 20288426 40576852 50721065 101442130 202884260 253605325 507210650 1014421300