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10145023662119 is a prime number
BaseRepresentation
bin1001001110100001001010…
…0010000001100000100111
31022220212002010211121110112
42103220102202001200213
52312204002024141434
633324320505243235
72064645100211663
oct223502242014047
938825063747415
1010145023662119
113261531416935
12117a20ba9351b
13587896742348
14271043a1b8a3
15128d66be1dce
hex93a12881827

10145023662119 has 2 divisors, whose sum is σ = 10145023662120. Its totient is φ = 10145023662118.

The previous prime is 10145023662101. The next prime is 10145023662121. The reversal of 10145023662119 is 91126632054101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10145023662119 is a prime.

It is a super-2 number, since 2×101450236621192 (a number of 27 digits) contains 22 as substring.

Together with 10145023662121, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10145023662139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5072511831059 + 5072511831060.

It is an arithmetic number, because the mean of its divisors is an integer number (5072511831060).

Almost surely, 210145023662119 is an apocalyptic number.

10145023662119 is a deficient number, since it is larger than the sum of its proper divisors (1).

10145023662119 is an equidigital number, since it uses as much as digits as its factorization.

10145023662119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 77760, while the sum is 41.

The spelling of 10145023662119 in words is "ten trillion, one hundred forty-five billion, twenty-three million, six hundred sixty-two thousand, one hundred nineteen".