Base | Representation |
---|---|
bin | 10010111001110001… |
… | …01111011111001101 |
3 | 222012020211201100211 |
4 | 21130320233133031 |
5 | 131240432004122 |
6 | 4355001322421 |
7 | 506325144322 |
oct | 113470573715 |
9 | 28166751324 |
10 | 10148313037 |
11 | 4338504875 |
12 | 1b72796411 |
13 | c59648575 |
14 | 6c3b2cb49 |
15 | 3e5e07877 |
hex | 25ce2f7cd |
10148313037 has 4 divisors (see below), whose sum is σ = 10206973980. Its totient is φ = 10089652096.
The previous prime is 10148313011. The next prime is 10148313059. The reversal of 10148313037 is 73031384101.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 73031384101 = 13 ⋅5617798777.
It can be written as a sum of positive squares in 2 ways, for example, as 6792891561 + 3355421476 = 82419^2 + 57926^2 .
It is a cyclic number.
It is not a de Polignac number, because 10148313037 - 223 = 10139924429 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10148313337) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29330212 + ... + 29330557.
It is an arithmetic number, because the mean of its divisors is an integer number (2551743495).
Almost surely, 210148313037 is an apocalyptic number.
It is an amenable number.
10148313037 is a deficient number, since it is larger than the sum of its proper divisors (58660943).
10148313037 is an equidigital number, since it uses as much as digits as its factorization.
10148313037 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 58660942.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 10148313037 its reverse (73031384101), we get a palindrome (83179697138).
The spelling of 10148313037 in words is "ten billion, one hundred forty-eight million, three hundred thirteen thousand, thirty-seven".
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