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1014838801853 = 17213833279173
BaseRepresentation
bin11101100010010010001…
…10110011010110111101
310121000110212020122212212
432301021012303112331
5113111342213124403
62054113245310205
7133214436326012
oct16611106632675
93530425218785
101014838801853
113614330573a8
12144823565365
13749115c4976
14371930a9709
151b5e93384d8
hexec491b35bd

1014838801853 has 8 divisors (see below), whose sum is σ = 1074544076088. Its totient is φ = 955134513664.

The previous prime is 1014838801849. The next prime is 1014838801883. The reversal of 1014838801853 is 3581088384101.

It can be written as a sum of positive squares in 4 ways, for example, as 509336287684 + 505502514169 = 713678^2 + 710987^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1014838801853 - 22 = 1014838801849 is a prime.

It is a super-3 number, since 3×10148388018533 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1014838801883) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3495575 + ... + 3774747.

It is an arithmetic number, because the mean of its divisors is an integer number (134318009511).

Almost surely, 21014838801853 is an apocalyptic number.

It is an amenable number.

1014838801853 is a deficient number, since it is larger than the sum of its proper divisors (59705274235).

1014838801853 is a wasteful number, since it uses less digits than its factorization.

1014838801853 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 493023.

The product of its (nonzero) digits is 737280, while the sum is 50.

The spelling of 1014838801853 in words is "one trillion, fourteen billion, eight hundred thirty-eight million, eight hundred one thousand, eight hundred fifty-three".

Divisors: 1 17 213833 279173 3635161 4745941 59696400109 1014838801853