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10183141 is a prime number
BaseRepresentation
bin100110110110…
…000111100101
3201011100122101
4212312013211
510101330031
61002132101
7152361313
oct46660745
921140571
1010183141
115825821
1234b1031
132157037
1414d10b3
15d62361
hex9b61e5

10183141 has 2 divisors, whose sum is σ = 10183142. Its totient is φ = 10183140.

The previous prime is 10183081. The next prime is 10183193. The reversal of 10183141 is 14138101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5387041 + 4796100 = 2321^2 + 2190^2 .

It is a cyclic number.

It is not a de Polignac number, because 10183141 - 27 = 10183013 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10183441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5091570 + 5091571.

It is an arithmetic number, because the mean of its divisors is an integer number (5091571).

Almost surely, 210183141 is an apocalyptic number.

It is an amenable number.

10183141 is a deficient number, since it is larger than the sum of its proper divisors (1).

10183141 is an equidigital number, since it uses as much as digits as its factorization.

10183141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96, while the sum is 19.

The square root of 10183141 is about 3191.1034141814. The cubic root of 10183141 is about 216.7507384456.

The spelling of 10183141 in words is "ten million, one hundred eighty-three thousand, one hundred forty-one".