10201112113 has 2 divisors, whose sum is σ = 10201112114. Its totient is φ = 10201112112.

The previous prime is 10201112081. The next prime is 10201112147. The reversal of 10201112113 is 31121110201.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5229169969 + 4971942144 = 72313^2 + 70512^2 .

It is an emirp because it is prime and its reverse (31121110201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10201112113 - 2⁵ = 10201112081 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10201112093 and 10201112102.

It is not a weakly prime, because it can be changed into another prime (10201112813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5100556056 + 5100556057.

It is an arithmetic number, because the mean of its divisors is an integer number (5100556057).

Almost surely, 2^10201112113 is an apocalyptic number.

It is an amenable number.

10201112113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10201112113 is an equidigital number, since it uses as much as digits as its factorization.

10201112113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 10201112113 its reverse (31121110201), we get a palindrome (41322222314).

The spelling of 10201112113 in words is "ten billion, two hundred one million, one hundred twelve thousand, one hundred thirteen".