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102014117 is a prime number
BaseRepresentation
bin1100001010010…
…01110010100101
321002221212001122
412011021302211
5202103422432
614042303325
72346051152
oct605116245
9232855048
10102014117
1152647797
122a1b7b45
131819a4aa
14d797229
158e51612
hex6149ca5

102014117 has 2 divisors, whose sum is σ = 102014118. Its totient is φ = 102014116.

The previous prime is 102014071. The next prime is 102014123. The reversal of 102014117 is 711410201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 86694721 + 15319396 = 9311^2 + 3914^2 .

It is a cyclic number.

It is not a de Polignac number, because 102014117 - 26 = 102014053 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 102014095 and 102014104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102014137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51007058 + 51007059.

It is an arithmetic number, because the mean of its divisors is an integer number (51007059).

Almost surely, 2102014117 is an apocalyptic number.

It is an amenable number.

102014117 is a deficient number, since it is larger than the sum of its proper divisors (1).

102014117 is an equidigital number, since it uses as much as digits as its factorization.

102014117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 17.

The square root of 102014117 is about 10100.2038098248. The cubic root of 102014117 is about 467.2544271564.

Adding to 102014117 its reverse (711410201), we get a palindrome (813424318).

The spelling of 102014117 in words is "one hundred two million, fourteen thousand, one hundred seventeen".