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10202012113 is a prime number
BaseRepresentation
bin10011000000001011…
…00101100111010001
3222022222212220122111
421200011211213101
5131343203341423
64404200305321
7510546446356
oct114005454721
928288786574
1010202012113
114365851777
121b88772241
13c677ca577
146cad0a62d
153ea9b360d
hex2601659d1

10202012113 has 2 divisors, whose sum is σ = 10202012114. Its totient is φ = 10202012112.

The previous prime is 10202012111. The next prime is 10202012123. The reversal of 10202012113 is 31121020201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8477437329 + 1724574784 = 92073^2 + 41528^2 .

It is a cyclic number.

It is not a de Polignac number, because 10202012113 - 21 = 10202012111 is a prime.

Together with 10202012111, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 10202012093 and 10202012102.

It is not a weakly prime, because it can be changed into another prime (10202012111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5101006056 + 5101006057.

It is an arithmetic number, because the mean of its divisors is an integer number (5101006057).

Almost surely, 210202012113 is an apocalyptic number.

It is an amenable number.

10202012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10202012113 is an equidigital number, since it uses as much as digits as its factorization.

10202012113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 10202012113 its reverse (31121020201), we get a palindrome (41323032314).

The spelling of 10202012113 in words is "ten billion, two hundred two million, twelve thousand, one hundred thirteen".