Base | Representation |
---|---|
bin | 11101101100010001100… |
… | …11010110100001010011 |
3 | 10121112022122211021221210 |
4 | 32312020303112201103 |
5 | 113203333304141430 |
6 | 2100401410151203 |
7 | 133464365264505 |
oct | 16661063264123 |
9 | 3545278737853 |
10 | 1020202412115 |
11 | 363735735157 |
12 | 14587b882503 |
13 | 75287893653 |
14 | 3754157bd75 |
15 | 1b8101662b0 |
hex | ed88cd6853 |
1020202412115 has 64 divisors (see below), whose sum is σ = 1749412933632. Its totient is φ = 505896192000.
The previous prime is 1020202412083. The next prime is 1020202412171. The reversal of 1020202412115 is 5112142020201.
1020202412115 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 1020202412115 - 25 = 1020202412083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1020202412091 and 1020202412100.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6896214 + ... + 7042596.
It is an arithmetic number, because the mean of its divisors is an integer number (27334577088).
Almost surely, 21020202412115 is an apocalyptic number.
1020202412115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1020202412115 is a deficient number, since it is larger than the sum of its proper divisors (729210521517).
1020202412115 is a wasteful number, since it uses less digits than its factorization.
1020202412115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 146740.
The product of its (nonzero) digits is 320, while the sum is 21.
Adding to 1020202412115 its reverse (5112142020201), we get a palindrome (6132344432316).
The spelling of 1020202412115 in words is "one trillion, twenty billion, two hundred two million, four hundred twelve thousand, one hundred fifteen".
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