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10202041311 = 371124014971
BaseRepresentation
bin10011000000001011…
…01100101111011111
3222022222221101200220
421200011230233133
5131343210310221
64404201052423
7510546630450
oct114005545737
928288841626
1010202041311
114365871700
121b88787113
13c6780a947
146cad17127
153ea9bc0c6
hex26016cbdf

10202041311 has 24 divisors (see below), whose sum is σ = 17087720832. Its totient is φ = 5299760400.

The previous prime is 10202041303. The next prime is 10202041327. The reversal of 10202041311 is 11314020201.

It is not a de Polignac number, because 10202041311 - 23 = 10202041303 is a prime.

It is a super-2 number, since 2×102020413112 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10202041361) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2004945 + ... + 2010026.

It is an arithmetic number, because the mean of its divisors is an integer number (711988368).

Almost surely, 210202041311 is an apocalyptic number.

10202041311 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

10202041311 is a deficient number, since it is larger than the sum of its proper divisors (6885679521).

10202041311 is a wasteful number, since it uses less digits than its factorization.

10202041311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4015003 (or 4014992 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 10202041311 its reverse (11314020201), we get a palindrome (21516061512).

The spelling of 10202041311 in words is "ten billion, two hundred two million, forty-one thousand, three hundred eleven".

Divisors: 1 3 7 11 21 33 77 121 231 363 847 2541 4014971 12044913 28104797 44164681 84314391 132494043 309152767 485811491 927458301 1457434473 3400680437 10202041311