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102030122013 = 334010040671
BaseRepresentation
bin101111100000101111…
…0000001110000011101
3100202100122200020002220
41133001132001300131
53132424202401023
6114512203335553
710241254504401
oct1370136016035
9322318606086
10102030122013
113a2a8386896
12179358215b9
1398102a2481
144d1c91b101
1529c259c3e3
hex17c1781c1d

102030122013 has 4 divisors (see below), whose sum is σ = 136040162688. Its totient is φ = 68020081340.

The previous prime is 102030121993. The next prime is 102030122023. The reversal of 102030122013 is 310221030201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 102030122013 - 28 = 102030121757 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102030121983 and 102030122001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102030122023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17005020333 + ... + 17005020338.

It is an arithmetic number, because the mean of its divisors is an integer number (34010040672).

Almost surely, 2102030122013 is an apocalyptic number.

It is an amenable number.

102030122013 is a deficient number, since it is larger than the sum of its proper divisors (34010040675).

102030122013 is an equidigital number, since it uses as much as digits as its factorization.

102030122013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34010040674.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 102030122013 its reverse (310221030201), we get a palindrome (412251152214).

The spelling of 102030122013 in words is "one hundred two billion, thirty million, one hundred twenty-two thousand, thirteen".

Divisors: 1 3 34010040671 102030122013