1020440100113 has 4 divisors (see below), whose sum is σ = 1166217257280. Its totient is φ = 874662942948.

The previous prime is 1020440100083. The next prime is 1020440100133. The reversal of 1020440100113 is 3110010440201.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1020440100113 - 2⁸ = 1020440099857 is a prime.

It is a super-2 number, since 2×1020440100113² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1020440100091 and 1020440100100.

It is not an unprimeable number, because it can be changed into a prime (1020440100133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72888578573 + ... + 72888578586.

It is an arithmetic number, because the mean of its divisors is an integer number (291554314320).

Almost surely, 2^{1020440100113} is an apocalyptic number.

It is an amenable number.

1020440100113 is a deficient number, since it is larger than the sum of its proper divisors (145777157167).

1020440100113 is an equidigital number, since it uses as much as digits as its factorization.

1020440100113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 145777157166.

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1020440100113 its reverse (3110010440201), we get a palindrome (4130450540314).

The spelling of 1020440100113 in words is "one trillion, twenty billion, four hundred forty million, one hundred thousand, one hundred thirteen".