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102100110113 is a prime number
BaseRepresentation
bin101111100010110100…
…1000000101100100001
3100202112112100222201202
41133011221000230201
53133100112010423
6114523143410545
710243064421341
oct1370551005441
9322475328652
10102100110113
113a3339399a1
1217955153a55
139821938751
144d27d38d21
1529c87c4728
hex17c5a40b21

102100110113 has 2 divisors, whose sum is σ = 102100110114. Its totient is φ = 102100110112.

The previous prime is 102100110041. The next prime is 102100110157. The reversal of 102100110113 is 311011001201.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101027351104 + 1072759009 = 317848^2 + 32753^2 .

It is an emirp because it is prime and its reverse (311011001201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102100110113 - 28 = 102100109857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 102100110094 and 102100110103.

It is not a weakly prime, because it can be changed into another prime (102100110173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51050055056 + 51050055057.

It is an arithmetic number, because the mean of its divisors is an integer number (51050055057).

Almost surely, 2102100110113 is an apocalyptic number.

It is an amenable number.

102100110113 is a deficient number, since it is larger than the sum of its proper divisors (1).

102100110113 is an equidigital number, since it uses as much as digits as its factorization.

102100110113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 102100110113 its reverse (311011001201), we get a palindrome (413111111314).

The spelling of 102100110113 in words is "one hundred two billion, one hundred million, one hundred ten thousand, one hundred thirteen".