Base | Representation |
---|---|
bin | 101111100010110100… |
… | …1000000101100100001 |
3 | 100202112112100222201202 |
4 | 1133011221000230201 |
5 | 3133100112010423 |
6 | 114523143410545 |
7 | 10243064421341 |
oct | 1370551005441 |
9 | 322475328652 |
10 | 102100110113 |
11 | 3a3339399a1 |
12 | 17955153a55 |
13 | 9821938751 |
14 | 4d27d38d21 |
15 | 29c87c4728 |
hex | 17c5a40b21 |
102100110113 has 2 divisors, whose sum is σ = 102100110114. Its totient is φ = 102100110112.
The previous prime is 102100110041. The next prime is 102100110157. The reversal of 102100110113 is 311011001201.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 101027351104 + 1072759009 = 317848^2 + 32753^2 .
It is an emirp because it is prime and its reverse (311011001201) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 102100110113 - 28 = 102100109857 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 102100110094 and 102100110103.
It is not a weakly prime, because it can be changed into another prime (102100110173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51050055056 + 51050055057.
It is an arithmetic number, because the mean of its divisors is an integer number (51050055057).
Almost surely, 2102100110113 is an apocalyptic number.
It is an amenable number.
102100110113 is a deficient number, since it is larger than the sum of its proper divisors (1).
102100110113 is an equidigital number, since it uses as much as digits as its factorization.
102100110113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 102100110113 its reverse (311011001201), we get a palindrome (413111111314).
The spelling of 102100110113 in words is "one hundred two billion, one hundred million, one hundred ten thousand, one hundred thirteen".
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