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10210101100411 is a prime number
BaseRepresentation
bin1001010010010011100101…
…1100101111111101111011
31100011002001111112000010211
42110210321130233331323
52314240241340203121
633414242232451551
72102440552260532
oct224447134577573
940132044460124
1010210101100411
113287096992493
12118a952249bb7
13590a680a2494
1427425896d319
1512a8c5095ce1
hex9493972ff7b

10210101100411 has 2 divisors, whose sum is σ = 10210101100412. Its totient is φ = 10210101100410.

The previous prime is 10210101100379. The next prime is 10210101100439. The reversal of 10210101100411 is 11400110101201.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 10210101100411 - 25 = 10210101100379 is a prime.

It is a super-2 number, since 2×102101011004112 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10210101100391 and 10210101100400.

It is not a weakly prime, because it can be changed into another prime (10210101107411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105050550205 + 5105050550206.

It is an arithmetic number, because the mean of its divisors is an integer number (5105050550206).

Almost surely, 210210101100411 is an apocalyptic number.

10210101100411 is a deficient number, since it is larger than the sum of its proper divisors (1).

10210101100411 is an equidigital number, since it uses as much as digits as its factorization.

10210101100411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 10210101100411 its reverse (11400110101201), we get a palindrome (21610211201612).

The spelling of 10210101100411 in words is "ten trillion, two hundred ten billion, one hundred one million, one hundred thousand, four hundred eleven".