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102110101981 is a prime number
BaseRepresentation
bin101111100011000111…
…1001000000111011101
3100202120020011121222221
41133012033020013131
53133110141230411
6114524141505341
710243245355216
oct1370617100735
9322506147887
10102110101981
113a339543a38
1217958572251
139823a266b4
144d293ba40d
1529c95ea071
hex17c63c81dd

102110101981 has 2 divisors, whose sum is σ = 102110101982. Its totient is φ = 102110101980.

The previous prime is 102110101969. The next prime is 102110101993. The reversal of 102110101981 is 189101011201.

It is a balanced prime because it is at equal distance from previous prime (102110101969) and next prime (102110101993).

It can be written as a sum of positive squares in only one way, i.e., 77815892025 + 24294209956 = 278955^2 + 155866^2 .

It is an emirp because it is prime and its reverse (189101011201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102110101981 - 25 = 102110101949 is a prime.

It is a super-2 number, since 2×1021101019812 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102110101381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055050990 + 51055050991.

It is an arithmetic number, because the mean of its divisors is an integer number (51055050991).

Almost surely, 2102110101981 is an apocalyptic number.

It is an amenable number.

102110101981 is a deficient number, since it is larger than the sum of its proper divisors (1).

102110101981 is an equidigital number, since it uses as much as digits as its factorization.

102110101981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 25.

The spelling of 102110101981 in words is "one hundred two billion, one hundred ten million, one hundred one thousand, nine hundred eighty-one".