Base | Representation |
---|---|
bin | 10111001101111001011100… |
… | …011010110110111111110111 |
3 | 111101112122000122110022220211 |
4 | 113031321130122312333313 |
5 | 101340432442334234431 |
6 | 1001100422254010251 |
7 | 30336132354064024 |
oct | 2715713432667767 |
9 | 441478018408824 |
10 | 102110103039991 |
11 | 2a598719185592 |
12 | b551756aa6987 |
13 | 44c8c31343607 |
14 | 1b3022642854b |
15 | bc11b894a2b1 |
hex | 5cde5c6b6ff7 |
102110103039991 has 2 divisors, whose sum is σ = 102110103039992. Its totient is φ = 102110103039990.
The previous prime is 102110103039943. The next prime is 102110103040031. The reversal of 102110103039991 is 199930301011201.
It is an a-pointer prime, because the next prime (102110103040031) can be obtained adding 102110103039991 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 102110103039991 - 215 = 102110103007223 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102110103069991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51055051519995 + 51055051519996.
It is an arithmetic number, because the mean of its divisors is an integer number (51055051519996).
Almost surely, 2102110103039991 is an apocalyptic number.
102110103039991 is a deficient number, since it is larger than the sum of its proper divisors (1).
102110103039991 is an equidigital number, since it uses as much as digits as its factorization.
102110103039991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 40.
The spelling of 102110103039991 in words is "one hundred two trillion, one hundred ten billion, one hundred three million, thirty-nine thousand, nine hundred ninety-one".
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