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1021111122113 is a prime number
BaseRepresentation
bin11101101101111101111…
…01110011100011000001
310121121122222201112201122
432312332331303203001
5113212213421401423
62101031511042025
7133526041221005
oct16667675634301
93547588645648
101021111122113
11364061676455
12145a94070315
13753a0c19684
14375ca124705
151b864d138c8
hexedbef738c1

1021111122113 has 2 divisors, whose sum is σ = 1021111122114. Its totient is φ = 1021111122112.

The previous prime is 1021111122077. The next prime is 1021111122127. The reversal of 1021111122113 is 3112211111201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 612749225089 + 408361897024 = 782783^2 + 639032^2 .

It is an emirp because it is prime and its reverse (3112211111201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1021111122113 - 236 = 952391645377 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1021111122091 and 1021111122100.

It is not a weakly prime, because it can be changed into another prime (1021111122013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510555561056 + 510555561057.

It is an arithmetic number, because the mean of its divisors is an integer number (510555561057).

Almost surely, 21021111122113 is an apocalyptic number.

It is an amenable number.

1021111122113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021111122113 is an equidigital number, since it uses as much as digits as its factorization.

1021111122113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 1021111122113 its reverse (3112211111201), we get a palindrome (4133322233314).

The spelling of 1021111122113 in words is "one trillion, twenty-one billion, one hundred eleven million, one hundred twenty-two thousand, one hundred thirteen".