Base | Representation |
---|---|
bin | 11101101101111101111… |
… | …01110011100011001111 |
3 | 10121121122222201112202011 |
4 | 32312332331303203033 |
5 | 113212213421402002 |
6 | 2101031511042051 |
7 | 133526041221025 |
oct | 16667675634317 |
9 | 3547588645664 |
10 | 1021111122127 |
11 | 364061676468 |
12 | 145a94070327 |
13 | 753a0c19695 |
14 | 375ca124715 |
15 | 1b864d138d7 |
hex | edbef738cf |
1021111122127 has 2 divisors, whose sum is σ = 1021111122128. Its totient is φ = 1021111122126.
The previous prime is 1021111122113. The next prime is 1021111122191. The reversal of 1021111122127 is 7212211111201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021111122127 - 211 = 1021111120079 is a prime.
It is a super-2 number, since 2×10211111221272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1021111122098 and 1021111122107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021111122827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510555561063 + 510555561064.
It is an arithmetic number, because the mean of its divisors is an integer number (510555561064).
Almost surely, 21021111122127 is an apocalyptic number.
1021111122127 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021111122127 is an equidigital number, since it uses as much as digits as its factorization.
1021111122127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 1021111122127 its reverse (7212211111201), we get a palindrome (8233322233328).
The spelling of 1021111122127 in words is "one trillion, twenty-one billion, one hundred eleven million, one hundred twenty-two thousand, one hundred twenty-seven".
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