Base | Representation |
---|---|
bin | 1001010010010111011001… |
… | …0011001011010011111011 |
3 | 1100011011200122112010200012 |
4 | 2110211312103023103323 |
5 | 2314244334213014042 |
6 | 33414531422132135 |
7 | 2102505056631524 |
oct | 224456623132373 |
9 | 40134618463605 |
10 | 10211122001147 |
11 | 3287570191301 |
12 | 118ab9812104b |
13 | 590b9b749a62 |
14 | 27431439b84b |
15 | 12a934a04e82 |
hex | 949764cb4fb |
10211122001147 has 2 divisors, whose sum is σ = 10211122001148. Its totient is φ = 10211122001146.
The previous prime is 10211122001081. The next prime is 10211122001149. The reversal of 10211122001147 is 74110022111201.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10211122001147 is a prime.
Together with 10211122001149, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10211122001149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5105561000573 + 5105561000574.
It is an arithmetic number, because the mean of its divisors is an integer number (5105561000574).
Almost surely, 210211122001147 is an apocalyptic number.
10211122001147 is a deficient number, since it is larger than the sum of its proper divisors (1).
10211122001147 is an equidigital number, since it uses as much as digits as its factorization.
10211122001147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 224, while the sum is 23.
Adding to 10211122001147 its reverse (74110022111201), we get a palindrome (84321144112348).
The spelling of 10211122001147 in words is "ten trillion, two hundred eleven billion, one hundred twenty-two million, one thousand, one hundred forty-seven".
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