102112121100131 has 2 divisors, whose sum is σ = 102112121100132. Its totient is φ = 102112121100130.

The previous prime is 102112121100103. The next prime is 102112121100133. The reversal of 102112121100131 is 131001121211201.

It is a strong prime.

It is an emirp because it is prime and its reverse (131001121211201) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-102112121100131 is a prime.

It is a super-2 number, since 2×102112121100131² (a number of 29 digits) contains 22 as substring.

Together with 102112121100133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (102112121100133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51056060550065 + 51056060550066.

It is an arithmetic number, because the mean of its divisors is an integer number (51056060550066).

Almost surely, 2^{102112121100131} is an apocalyptic number.

102112121100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

102112121100131 is an equidigital number, since it uses as much as digits as its factorization.

102112121100131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 102112121100131 its reverse (131001121211201), we get a palindrome (233113242311332).

The spelling of 102112121100131 in words is "one hundred two trillion, one hundred twelve billion, one hundred twenty-one million, one hundred thousand, one hundred thirty-one".