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10211220133 = 49920463367
BaseRepresentation
bin10011000001010001…
…01101101010100101
3222100122012201200021
421200220231222211
5131403033021013
64405125515141
7511020640042
oct114050555245
928318181607
1010211220133
11436aa70904
121b8b872ab1
13c696a27ba
146cc2261c9
153eb6d1a8d
hex260a2daa5

10211220133 has 4 divisors (see below), whose sum is σ = 10231684000. Its totient is φ = 10190756268.

The previous prime is 10211220127. The next prime is 10211220181. The reversal of 10211220133 is 33102211201.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10211220133 - 25 = 10211220101 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10211220113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10231185 + ... + 10232182.

It is an arithmetic number, because the mean of its divisors is an integer number (2557921000).

Almost surely, 210211220133 is an apocalyptic number.

It is an amenable number.

10211220133 is a deficient number, since it is larger than the sum of its proper divisors (20463867).

10211220133 is an equidigital number, since it uses as much as digits as its factorization.

10211220133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20463866.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 10211220133 its reverse (33102211201), we get a palindrome (43313431334).

The spelling of 10211220133 in words is "ten billion, two hundred eleven million, two hundred twenty thousand, one hundred thirty-three".

Divisors: 1 499 20463367 10211220133