10211302113 has 4 divisors (see below), whose sum is σ = 13615069488. Its totient is φ = 6807534740.

The previous prime is 10211302097. The next prime is 10211302117. The reversal of 10211302113 is 31120311201.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10211302113 - 2⁴ = 10211302097 is a prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10211302092 and 10211302101.

It is not an unprimeable number, because it can be changed into a prime (10211302117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1701883683 + ... + 1701883688.

It is an arithmetic number, because the mean of its divisors is an integer number (3403767372).

Almost surely, 2^10211302113 is an apocalyptic number.

It is an amenable number.

10211302113 is a deficient number, since it is larger than the sum of its proper divisors (3403767375).

10211302113 is an equidigital number, since it uses as much as digits as its factorization.

10211302113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3403767374.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 10211302113 its reverse (31120311201), we get a palindrome (41331613314).

The spelling of 10211302113 in words is "ten billion, two hundred eleven million, three hundred two thousand, one hundred thirteen".