Base | Representation |
---|---|
bin | 10111001101111100001111… |
… | …110001001101010000100011 |
3 | 111101112220210100101100111222 |
4 | 113031330033301031100203 |
5 | 101341010123134120003 |
6 | 1001102041022525255 |
7 | 30336300052020350 |
oct | 2715741761152043 |
9 | 441486710340458 |
10 | 102113112020003 |
11 | 2a599a22719827 |
12 | b55225673682b |
13 | 44c92c0850366 |
14 | 1b3042dccb627 |
15 | bc12e2bb4c38 |
hex | 5cdf0fc4d423 |
102113112020003 has 4 divisors (see below), whose sum is σ = 116700699451440. Its totient is φ = 87525524588568.
The previous prime is 102113112019991. The next prime is 102113112020189. The reversal of 102113112020003 is 300020211311201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 102113112020003 - 212 = 102113112015907 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (102113112020303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7293793715708 + ... + 7293793715721.
It is an arithmetic number, because the mean of its divisors is an integer number (29175174862860).
Almost surely, 2102113112020003 is an apocalyptic number.
102113112020003 is a deficient number, since it is larger than the sum of its proper divisors (14587587431437).
102113112020003 is an equidigital number, since it uses as much as digits as its factorization.
102113112020003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14587587431436.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 102113112020003 its reverse (300020211311201), we get a palindrome (402133323331204).
The spelling of 102113112020003 in words is "one hundred two trillion, one hundred thirteen billion, one hundred twelve million, twenty thousand, three".
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