102113300212313 has 4 divisors (see below), whose sum is σ = 109968169459428. Its totient is φ = 94258430965200.

The previous prime is 102113300212303. The next prime is 102113300212381. The reversal of 102113300212313 is 313212003311201.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 30660716732944 + 71452583479369 = 5537212^2 + 8452963^2 .

It is a cyclic number.

It is not a de Polignac number, because 102113300212313 - 2⁸ = 102113300212057 is a prime.

It is a super-3 number, since 3×102113300212313³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (102113300212303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3927434623538 + ... + 3927434623563.

It is an arithmetic number, because the mean of its divisors is an integer number (27492042364857).

Almost surely, 2^{102113300212313} is an apocalyptic number.

102113300212313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

102113300212313 is a deficient number, since it is larger than the sum of its proper divisors (7854869247115).

102113300212313 is an equidigital number, since it uses as much as digits as its factorization.

102113300212313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7854869247114.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 102113300212313 its reverse (313212003311201), we get a palindrome (415325303523514).

The spelling of 102113300212313 in words is "one hundred two trillion, one hundred thirteen billion, three hundred million, two hundred twelve thousand, three hundred thirteen".