Base | Representation |
---|---|
bin | 101111100011001111… |
… | …0000010100000000111 |
3 | 100202120111112020100201 |
4 | 1133012132002200013 |
5 | 3133112141324033 |
6 | 114524401351331 |
7 | 10243323526204 |
oct | 1370636024007 |
9 | 322514466321 |
10 | 102114011143 |
11 | 3a340773a51 |
12 | 17959938547 |
13 | 9824794b01 |
14 | 4d29b16cab |
15 | 29c9b1d47d |
hex | 17c6782807 |
102114011143 has 4 divisors (see below), whose sum is σ = 104873849320. Its totient is φ = 99354172968.
The previous prime is 102114011137. The next prime is 102114011147. The reversal of 102114011143 is 341110411201.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 102114011143 - 29 = 102114010631 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 102114011143.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102114011147) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1379919033 + ... + 1379919106.
It is an arithmetic number, because the mean of its divisors is an integer number (26218462330).
Almost surely, 2102114011143 is an apocalyptic number.
102114011143 is a deficient number, since it is larger than the sum of its proper divisors (2759838177).
102114011143 is an equidigital number, since it uses as much as digits as its factorization.
102114011143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2759838176.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 102114011143 its reverse (341110411201), we get a palindrome (443224422344).
The spelling of 102114011143 in words is "one hundred two billion, one hundred fourteen million, eleven thousand, one hundred forty-three".
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