Base | Representation |
---|---|
bin | 101111100011011011… |
… | …0011010100111100101 |
3 | 100202120221112220010012 |
4 | 1133012312122213211 |
5 | 3133120310321011 |
6 | 114525150340005 |
7 | 10243432042505 |
oct | 1370666324745 |
9 | 322527486105 |
10 | 102120401381 |
11 | 3a344339039 |
12 | 1795baba605 |
13 | 9825bc160b |
14 | 4d2a8dba05 |
15 | 29ca481a8b |
hex | 17c6d9a9e5 |
102120401381 has 2 divisors, whose sum is σ = 102120401382. Its totient is φ = 102120401380.
The previous prime is 102120401363. The next prime is 102120401387. The reversal of 102120401381 is 183104021201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66613029025 + 35507372356 = 258095^2 + 188434^2 .
It is a cyclic number.
It is not a de Polignac number, because 102120401381 - 234 = 84940532197 is a prime.
It is a super-2 number, since 2×1021204013812 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102120401387) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51060200690 + 51060200691.
It is an arithmetic number, because the mean of its divisors is an integer number (51060200691).
Almost surely, 2102120401381 is an apocalyptic number.
It is an amenable number.
102120401381 is a deficient number, since it is larger than the sum of its proper divisors (1).
102120401381 is an equidigital number, since it uses as much as digits as its factorization.
102120401381 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 102120401381 its reverse (183104021201), we get a palindrome (285224422582).
The spelling of 102120401381 in words is "one hundred two billion, one hundred twenty million, four hundred one thousand, three hundred eighty-one".
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