Base | Representation |
---|---|
bin | 1001010010011011000010… |
… | …0110010101010010000011 |
3 | 1100011021012210222202202222 |
4 | 2110212300212111102003 |
5 | 2314303340111220001 |
6 | 33415212442201255 |
7 | 2102541234431366 |
oct | 224466046252203 |
9 | 40137183882688 |
10 | 10212100101251 |
11 | 3287a223073a4 |
12 | 118b20b7b322b |
13 | 590cc6289b09 |
14 | 2743a82480dd |
15 | 12a99080c61b |
hex | 949b0995483 |
10212100101251 has 2 divisors, whose sum is σ = 10212100101252. Its totient is φ = 10212100101250.
The previous prime is 10212100101227. The next prime is 10212100101253. The reversal of 10212100101251 is 15210100121201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10212100101251 - 214 = 10212100084867 is a prime.
Together with 10212100101253, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10212100101253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106050050625 + 5106050050626.
It is an arithmetic number, because the mean of its divisors is an integer number (5106050050626).
Almost surely, 210212100101251 is an apocalyptic number.
10212100101251 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212100101251 is an equidigital number, since it uses as much as digits as its factorization.
10212100101251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 10212100101251 its reverse (15210100121201), we get a palindrome (25422200222452).
The spelling of 10212100101251 in words is "ten trillion, two hundred twelve billion, one hundred million, one hundred one thousand, two hundred fifty-one".
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