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102121120000103 is a prime number
BaseRepresentation
bin10111001110000011101101…
…000101001110100001100111
3111101120200110102210220001112
4113032003231011032201213
5101341123023210000403
61001105443405415235
730340002360515201
oct2716035505164147
9441520412726045
10102121120000103
112a5a2361a477a6
12b55391056a51b
1344c9c98928819
141b3098d671771
15bc1610c399d8
hex5ce0ed14e867

102121120000103 has 2 divisors, whose sum is σ = 102121120000104. Its totient is φ = 102121120000102.

The previous prime is 102121120000007. The next prime is 102121120000117. The reversal of 102121120000103 is 301000021121201.

It is an a-pointer prime, because the next prime (102121120000117) can be obtained adding 102121120000103 to its sum of digits (14).

It is a strong prime.

It is an emirp because it is prime and its reverse (301000021121201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 102121120000103 - 214 = 102121119983719 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102121120090103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51060560000051 + 51060560000052.

It is an arithmetic number, because the mean of its divisors is an integer number (51060560000052).

Almost surely, 2102121120000103 is an apocalyptic number.

102121120000103 is a deficient number, since it is larger than the sum of its proper divisors (1).

102121120000103 is an equidigital number, since it uses as much as digits as its factorization.

102121120000103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 102121120000103 its reverse (301000021121201), we get a palindrome (403121141121304).

The spelling of 102121120000103 in words is "one hundred two trillion, one hundred twenty-one billion, one hundred twenty million, one hundred three", and thus it is an aban number.