Base | Representation |
---|---|
bin | 1001010010011011000101… |
… | …0011101110010001000011 |
3 | 1100011021020122101021212212 |
4 | 2110212301103232101003 |
5 | 2314303401133000232 |
6 | 33415213545212335 |
7 | 2102541440526665 |
oct | 224466123562103 |
9 | 40137218337785 |
10 | 10212112000067 |
11 | 3287a28aa412a |
12 | 118b2137910ab |
13 | 590cc8894a33 |
14 | 2743a9a64535 |
15 | 12a9918aceb2 |
hex | 949b14ee443 |
10212112000067 has 2 divisors, whose sum is σ = 10212112000068. Its totient is φ = 10212112000066.
The previous prime is 10212112000007. The next prime is 10212112000093. The reversal of 10212112000067 is 76000021121201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10212112000067 - 242 = 5814065488963 is a prime.
It is a super-3 number, since 3×102121120000673 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (10212112000007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106056000033 + 5106056000034.
It is an arithmetic number, because the mean of its divisors is an integer number (5106056000034).
Almost surely, 210212112000067 is an apocalyptic number.
10212112000067 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212112000067 is an equidigital number, since it uses as much as digits as its factorization.
10212112000067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 10212112000067 its reverse (76000021121201), we get a palindrome (86212133121268).
The spelling of 10212112000067 in words is "ten trillion, two hundred twelve billion, one hundred twelve million, sixty-seven", and thus it is an aban number.
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