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102121120111103 is a prime number
BaseRepresentation
bin10111001110000011101101…
…000101101001100111111111
3111101120200110110000112022122
4113032003231011221213333
5101341123023222023403
61001105443412033155
730340002361456622
oct2716035505514777
9441520413015278
10102121120111103
112a5a2362013135
12b5539106027bb
1344c9c989671c2
141b3098d69ddb9
15bc1610c5c838
hex5ce0ed1699ff

102121120111103 has 2 divisors, whose sum is σ = 102121120111104. Its totient is φ = 102121120111102.

The previous prime is 102121120111013. The next prime is 102121120111139. The reversal of 102121120111103 is 301111021121201.

Together with previous prime (102121120111013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-102121120111103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102121120111603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51060560055551 + 51060560055552.

It is an arithmetic number, because the mean of its divisors is an integer number (51060560055552).

Almost surely, 2102121120111103 is an apocalyptic number.

102121120111103 is a deficient number, since it is larger than the sum of its proper divisors (1).

102121120111103 is an equidigital number, since it uses as much as digits as its factorization.

102121120111103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 102121120111103 its reverse (301111021121201), we get a palindrome (403232141232304).

The spelling of 102121120111103 in words is "one hundred two trillion, one hundred twenty-one billion, one hundred twenty million, one hundred eleven thousand, one hundred three".