Base | Representation |
---|---|
bin | 10111001110000011101101… |
… | …000101101001100111111111 |
3 | 111101120200110110000112022122 |
4 | 113032003231011221213333 |
5 | 101341123023222023403 |
6 | 1001105443412033155 |
7 | 30340002361456622 |
oct | 2716035505514777 |
9 | 441520413015278 |
10 | 102121120111103 |
11 | 2a5a2362013135 |
12 | b5539106027bb |
13 | 44c9c989671c2 |
14 | 1b3098d69ddb9 |
15 | bc1610c5c838 |
hex | 5ce0ed1699ff |
102121120111103 has 2 divisors, whose sum is σ = 102121120111104. Its totient is φ = 102121120111102.
The previous prime is 102121120111013. The next prime is 102121120111139. The reversal of 102121120111103 is 301111021121201.
Together with previous prime (102121120111013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102121120111103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102121120111603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51060560055551 + 51060560055552.
It is an arithmetic number, because the mean of its divisors is an integer number (51060560055552).
Almost surely, 2102121120111103 is an apocalyptic number.
102121120111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
102121120111103 is an equidigital number, since it uses as much as digits as its factorization.
102121120111103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 102121120111103 its reverse (301111021121201), we get a palindrome (403232141232304).
The spelling of 102121120111103 in words is "one hundred two trillion, one hundred twenty-one billion, one hundred twenty million, one hundred eleven thousand, one hundred three".
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