Base | Representation |
---|---|
bin | 11101101110001001111… |
… | …11110100001000100111 |
3 | 10121121221001010112022001 |
4 | 32313010333310020213 |
5 | 113212420322441403 |
6 | 2101045523550131 |
7 | 133531410300364 |
oct | 16670477641047 |
9 | 3547831115261 |
10 | 1021212312103 |
11 | 3641037aaa45 |
12 | 145b01b2b347 |
13 | 753b8b889c9 |
14 | 375d974546b |
15 | 1b86db50c1d |
hex | edc4ff4227 |
1021212312103 has 2 divisors, whose sum is σ = 1021212312104. Its totient is φ = 1021212312102.
The previous prime is 1021212312097. The next prime is 1021212312121. The reversal of 1021212312103 is 3012132121201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021212312103 - 213 = 1021212303911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021212312193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510606156051 + 510606156052.
It is an arithmetic number, because the mean of its divisors is an integer number (510606156052).
Almost surely, 21021212312103 is an apocalyptic number.
1021212312103 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021212312103 is an equidigital number, since it uses as much as digits as its factorization.
1021212312103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1021212312103 its reverse (3012132121201), we get a palindrome (4033344433304).
The spelling of 1021212312103 in words is "one trillion, twenty-one billion, two hundred twelve million, three hundred twelve thousand, one hundred three".
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