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1021220133149 is a prime number
BaseRepresentation
bin11101101110001010111…
…01101001100100011101
310121121221120211212202102
432313011131221210131
5113212424323230044
62101050403334445
7133531533623306
oct16670535514435
93547846755672
101021220133149
11364108162017
12145b04681425
13753ba696848
14375da7bd7ad
151b86e69824e
hexedc576991d

1021220133149 has 2 divisors, whose sum is σ = 1021220133150. Its totient is φ = 1021220133148.

The previous prime is 1021220133107. The next prime is 1021220133161. The reversal of 1021220133149 is 9413310221201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 859547785924 + 161672347225 = 927118^2 + 402085^2 .

It is a cyclic number.

It is not a de Polignac number, because 1021220133149 - 224 = 1021203355933 is a prime.

It is a super-2 number, since 2×10212201331492 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1021220136149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510610066574 + 510610066575.

It is an arithmetic number, because the mean of its divisors is an integer number (510610066575).

Almost surely, 21021220133149 is an apocalyptic number.

It is an amenable number.

1021220133149 is a deficient number, since it is larger than the sum of its proper divisors (1).

1021220133149 is an equidigital number, since it uses as much as digits as its factorization.

1021220133149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 29.

The spelling of 1021220133149 in words is "one trillion, twenty-one billion, two hundred twenty million, one hundred thirty-three thousand, one hundred forty-nine".