Base | Representation |
---|---|
bin | 10011000001011001… |
… | …00000010011111101 |
3 | 222100201002020000122 |
4 | 21200230200103331 |
5 | 131403311322023 |
6 | 4405203104325 |
7 | 511032246461 |
oct | 114054402375 |
9 | 28321066018 |
10 | 10212214013 |
11 | 437058a5a1 |
12 | 1b900720a5 |
13 | c6995ccb1 |
14 | 6cc4044a1 |
15 | 3eb82b2c8 |
hex | 260b204fd |
10212214013 has 2 divisors, whose sum is σ = 10212214014. Its totient is φ = 10212214012.
The previous prime is 10212213989. The next prime is 10212214021. The reversal of 10212214013 is 31041221201.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9987603844 + 224610169 = 99938^2 + 14987^2 .
It is a cyclic number.
It is not a de Polignac number, because 10212214013 - 216 = 10212148477 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10212213982 and 10212214000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10212214043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106107006 + 5106107007.
It is an arithmetic number, because the mean of its divisors is an integer number (5106107007).
Almost surely, 210212214013 is an apocalyptic number.
It is an amenable number.
10212214013 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212214013 is an equidigital number, since it uses as much as digits as its factorization.
10212214013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 10212214013 its reverse (31041221201), we get a palindrome (41253435214).
The spelling of 10212214013 in words is "ten billion, two hundred twelve million, two hundred fourteen thousand, thirteen".
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