Base | Representation |
---|---|
bin | 1001010010011011100100… |
… | …1001110101100111001111 |
3 | 1100011021120211001121022222 |
4 | 2110212321021311213033 |
5 | 2314304133332021242 |
6 | 33415235010325555 |
7 | 2102544626403242 |
oct | 224467111654717 |
9 | 40137524047288 |
10 | 10212243626447 |
11 | 3287a96326a65 |
12 | 118b24b8898bb |
13 | 591019c2c875 |
14 | 2743bd329259 |
15 | 12a99d20d5d2 |
hex | 949b92759cf |
10212243626447 has 2 divisors, whose sum is σ = 10212243626448. Its totient is φ = 10212243626446.
The previous prime is 10212243626441. The next prime is 10212243626449. The reversal of 10212243626447 is 74462634221201.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10212243626447 - 28 = 10212243626191 is a prime.
Together with 10212243626449, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 10212243626398 and 10212243626407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10212243626441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106121813223 + 5106121813224.
It is an arithmetic number, because the mean of its divisors is an integer number (5106121813224).
Almost surely, 210212243626447 is an apocalyptic number.
10212243626447 is a deficient number, since it is larger than the sum of its proper divisors (1).
10212243626447 is an equidigital number, since it uses as much as digits as its factorization.
10212243626447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 774144, while the sum is 44.
Adding to 10212243626447 its reverse (74462634221201), we get a palindrome (84674877847648).
The spelling of 10212243626447 in words is "ten trillion, two hundred twelve billion, two hundred forty-three million, six hundred twenty-six thousand, four hundred forty-seven".
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