Base | Representation |
---|---|
bin | 10111001110000101011110… |
… | …111111000111111111111101 |
3 | 111101120212101121200220101112 |
4 | 113032011132333013333331 |
5 | 101341140431414100013 |
6 | 1001110401153051405 |
7 | 30340100624002460 |
oct | 2716053677077775 |
9 | 441525347626345 |
10 | 102123031003133 |
11 | 2a5a3152728648 |
12 | b554164556b65 |
13 | 44ca21181264a |
14 | 1b30ad13a12d7 |
15 | bc16c38bcba8 |
hex | 5ce15efc7ffd |
102123031003133 has 4 divisors (see below), whose sum is σ = 116712035432160. Its totient is φ = 87534026574108.
The previous prime is 102123031003033. The next prime is 102123031003187. The reversal of 102123031003133 is 331300130321201.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 102123031003133 - 214 = 102123030986749 is a prime.
It is a super-2 number, since 2×1021230310031332 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 102123031003099 and 102123031003108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102123031003033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7294502214503 + ... + 7294502214516.
It is an arithmetic number, because the mean of its divisors is an integer number (29178008858040).
Almost surely, 2102123031003133 is an apocalyptic number.
It is an amenable number.
102123031003133 is a deficient number, since it is larger than the sum of its proper divisors (14589004429027).
102123031003133 is an equidigital number, since it uses as much as digits as its factorization.
102123031003133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14589004429026.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 102123031003133 its reverse (331300130321201), we get a palindrome (433423161324334).
The spelling of 102123031003133 in words is "one hundred two trillion, one hundred twenty-three billion, thirty-one million, three thousand, one hundred thirty-three".
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