Base | Representation |
---|---|
bin | 11101101110010001010… |
… | …00001000000101000111 |
3 | 10121122002021201112011102 |
4 | 32313020220020011013 |
5 | 113213031420224312 |
6 | 2101055541130315 |
7 | 133533050030654 |
oct | 16671050100507 |
9 | 3548067645142 |
10 | 1021273211207 |
11 | 364135115387 |
12 | 145b1a3b999b |
13 | 753c868bc92 |
14 | 37603878c2b |
15 | 1b87417eec2 |
hex | edc8a08147 |
1021273211207 has 2 divisors, whose sum is σ = 1021273211208. Its totient is φ = 1021273211206.
The previous prime is 1021273211201. The next prime is 1021273211297. The reversal of 1021273211207 is 7021123721201.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1021273211207 - 212 = 1021273207111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1021273211207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1021273211201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 510636605603 + 510636605604.
It is an arithmetic number, because the mean of its divisors is an integer number (510636605604).
Almost surely, 21021273211207 is an apocalyptic number.
1021273211207 is a deficient number, since it is larger than the sum of its proper divisors (1).
1021273211207 is an equidigital number, since it uses as much as digits as its factorization.
1021273211207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2352, while the sum is 29.
Adding to 1021273211207 its reverse (7021123721201), we get a palindrome (8042396932408).
The spelling of 1021273211207 in words is "one trillion, twenty-one billion, two hundred seventy-three million, two hundred eleven thousand, two hundred seven".
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