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1021300010222 = 2510650005111
BaseRepresentation
bin11101101110010100011…
…10010110110011101110
310121122011011011001111112
432313022032112303232
5113213110300311342
62101102335352022
7133533523565132
oct16671216266356
93548134131445
101021300010222
11364149259928
12145b27382612
13754010b2c9b
14376072533c2
151b8766c5682
hexedca396cee

1021300010222 has 4 divisors (see below), whose sum is σ = 1531950015336. Its totient is φ = 510650005110.

The previous prime is 1021300010201. The next prime is 1021300010243. The reversal of 1021300010222 is 2220100031201.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1021300010201) and next prime (1021300010243).

It is a super-3 number, since 3×10213000102223 (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1021300010197 and 1021300010206.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255325002554 + ... + 255325002557.

It is an arithmetic number, because the mean of its divisors is an integer number (382987503834).

Almost surely, 21021300010222 is an apocalyptic number.

1021300010222 is a deficient number, since it is larger than the sum of its proper divisors (510650005114).

1021300010222 is an equidigital number, since it uses as much as digits as its factorization.

1021300010222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 510650005113.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 1021300010222 its reverse (2220100031201), we get a palindrome (3241400041423).

The spelling of 1021300010222 in words is "one trillion, twenty-one billion, three hundred million, ten thousand, two hundred twenty-two".

Divisors: 1 2 510650005111 1021300010222