Base | Representation |
---|---|
bin | 10011000001011111… |
… | …00000010000001111 |
3 | 222100202120011110221 |
4 | 21200233200100033 |
5 | 131404012001312 |
6 | 4405232012211 |
7 | 511042032544 |
oct | 114057402017 |
9 | 28322504427 |
10 | 10213000207 |
11 | 4370a77243 |
12 | 1b90391067 |
13 | c69b76ab7 |
14 | 6cc56abcb |
15 | 3eb934207 |
hex | 260be040f |
10213000207 has 2 divisors, whose sum is σ = 10213000208. Its totient is φ = 10213000206.
The previous prime is 10213000181. The next prime is 10213000261. The reversal of 10213000207 is 70200031201.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10213000207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10213000507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5106500103 + 5106500104.
It is an arithmetic number, because the mean of its divisors is an integer number (5106500104).
Almost surely, 210213000207 is an apocalyptic number.
10213000207 is a deficient number, since it is larger than the sum of its proper divisors (1).
10213000207 is an equidigital number, since it uses as much as digits as its factorization.
10213000207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84, while the sum is 16.
Adding to 10213000207 its reverse (70200031201), we get a palindrome (80413031408).
The spelling of 10213000207 in words is "ten billion, two hundred thirteen million, two hundred seven", and thus it is an aban number.
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