Search a number
-
+
102130010213143 = 112844049671183
BaseRepresentation
bin10111001110001011111110…
…111110101100101100010111
3111101121112102000022111200011
4113032023332332230230113
5101341244230103310033
61001113513505501051
730340435601212513
oct2716137676545427
9441545360274604
10102130010213143
112a5a6104272400
12b555591941787
1344caa84719703
141b31194269143
15bc198147bccd
hex5ce2fefacb17

102130010213143 has 6 divisors (see below), whose sum is σ = 112258606267472. Its totient is φ = 92845463830020.

The previous prime is 102130010213141. The next prime is 102130010213207. The reversal of 102130010213143 is 341312010031201.

It is not a de Polignac number, because 102130010213143 - 21 = 102130010213141 is a prime.

It is a super-2 number, since 2×1021300102131432 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (102130010213141) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 422024835471 + ... + 422024835712.

Almost surely, 2102130010213143 is an apocalyptic number.

102130010213143 is a deficient number, since it is larger than the sum of its proper divisors (10128596054329).

102130010213143 is an equidigital number, since it uses as much as digits as its factorization.

102130010213143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 844049671205 (or 844049671194 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 102130010213143 its reverse (341312010031201), we get a palindrome (443442020244344).

The spelling of 102130010213143 in words is "one hundred two trillion, one hundred thirty billion, ten million, two hundred thirteen thousand, one hundred forty-three".

Divisors: 1 11 121 844049671183 9284546383013 102130010213143