Base | Representation |
---|---|
bin | 10111001110001011111110… |
… | …111110101100101100010111 |
3 | 111101121112102000022111200011 |
4 | 113032023332332230230113 |
5 | 101341244230103310033 |
6 | 1001113513505501051 |
7 | 30340435601212513 |
oct | 2716137676545427 |
9 | 441545360274604 |
10 | 102130010213143 |
11 | 2a5a6104272400 |
12 | b555591941787 |
13 | 44caa84719703 |
14 | 1b31194269143 |
15 | bc198147bccd |
hex | 5ce2fefacb17 |
102130010213143 has 6 divisors (see below), whose sum is σ = 112258606267472. Its totient is φ = 92845463830020.
The previous prime is 102130010213141. The next prime is 102130010213207. The reversal of 102130010213143 is 341312010031201.
It is not a de Polignac number, because 102130010213143 - 21 = 102130010213141 is a prime.
It is a super-2 number, since 2×1021300102131432 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (102130010213141) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 422024835471 + ... + 422024835712.
Almost surely, 2102130010213143 is an apocalyptic number.
102130010213143 is a deficient number, since it is larger than the sum of its proper divisors (10128596054329).
102130010213143 is an equidigital number, since it uses as much as digits as its factorization.
102130010213143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 844049671205 (or 844049671194 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 102130010213143 its reverse (341312010031201), we get a palindrome (443442020244344).
The spelling of 102130010213143 in words is "one hundred two trillion, one hundred thirty billion, ten million, two hundred thirteen thousand, one hundred forty-three".
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